Optimal. Leaf size=184 \[ \frac {4 \cos (c+d x) \, _2F_1\left (\frac {1}{6},\frac {1}{2};\frac {7}{6};\sin ^2(c+d x)\right ) \sqrt [3]{\sin (c+d x)}}{9 a^2 d \sqrt {\cos ^2(c+d x)}}-\frac {\cos (c+d x) \, _2F_1\left (\frac {1}{2},\frac {2}{3};\frac {5}{3};\sin ^2(c+d x)\right ) \sin ^{\frac {4}{3}}(c+d x)}{36 a^2 d \sqrt {\cos ^2(c+d x)}}-\frac {\cos (c+d x) \sqrt [3]{\sin (c+d x)}}{9 a^2 d (1+\sin (c+d x))}-\frac {\cos (c+d x) \sqrt [3]{\sin (c+d x)}}{3 d (a+a \sin (c+d x))^2} \]
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Rubi [A]
time = 0.15, antiderivative size = 184, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 4, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.174, Rules used = {2843, 3057,
2827, 2722} \begin {gather*} \frac {4 \sqrt [3]{\sin (c+d x)} \cos (c+d x) \, _2F_1\left (\frac {1}{6},\frac {1}{2};\frac {7}{6};\sin ^2(c+d x)\right )}{9 a^2 d \sqrt {\cos ^2(c+d x)}}-\frac {\sin ^{\frac {4}{3}}(c+d x) \cos (c+d x) \, _2F_1\left (\frac {1}{2},\frac {2}{3};\frac {5}{3};\sin ^2(c+d x)\right )}{36 a^2 d \sqrt {\cos ^2(c+d x)}}-\frac {\sqrt [3]{\sin (c+d x)} \cos (c+d x)}{9 a^2 d (\sin (c+d x)+1)}-\frac {\sqrt [3]{\sin (c+d x)} \cos (c+d x)}{3 d (a \sin (c+d x)+a)^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 2722
Rule 2827
Rule 2843
Rule 3057
Rubi steps
\begin {align*} \int \frac {\sqrt [3]{\sin (c+d x)}}{(a+a \sin (c+d x))^2} \, dx &=-\frac {\cos (c+d x) \sqrt [3]{\sin (c+d x)}}{3 d (a+a \sin (c+d x))^2}+\frac {\int \frac {\frac {a}{3}+\frac {2}{3} a \sin (c+d x)}{\sin ^{\frac {2}{3}}(c+d x) (a+a \sin (c+d x))} \, dx}{3 a^2}\\ &=-\frac {\cos (c+d x) \sqrt [3]{\sin (c+d x)}}{9 a^2 d (1+\sin (c+d x))}-\frac {\cos (c+d x) \sqrt [3]{\sin (c+d x)}}{3 d (a+a \sin (c+d x))^2}+\frac {\int \frac {\frac {4 a^2}{9}-\frac {1}{9} a^2 \sin (c+d x)}{\sin ^{\frac {2}{3}}(c+d x)} \, dx}{3 a^4}\\ &=-\frac {\cos (c+d x) \sqrt [3]{\sin (c+d x)}}{9 a^2 d (1+\sin (c+d x))}-\frac {\cos (c+d x) \sqrt [3]{\sin (c+d x)}}{3 d (a+a \sin (c+d x))^2}-\frac {\int \sqrt [3]{\sin (c+d x)} \, dx}{27 a^2}+\frac {4 \int \frac {1}{\sin ^{\frac {2}{3}}(c+d x)} \, dx}{27 a^2}\\ &=\frac {4 \cos (c+d x) \, _2F_1\left (\frac {1}{6},\frac {1}{2};\frac {7}{6};\sin ^2(c+d x)\right ) \sqrt [3]{\sin (c+d x)}}{9 a^2 d \sqrt {\cos ^2(c+d x)}}-\frac {\cos (c+d x) \, _2F_1\left (\frac {1}{2},\frac {2}{3};\frac {5}{3};\sin ^2(c+d x)\right ) \sin ^{\frac {4}{3}}(c+d x)}{36 a^2 d \sqrt {\cos ^2(c+d x)}}-\frac {\cos (c+d x) \sqrt [3]{\sin (c+d x)}}{9 a^2 d (1+\sin (c+d x))}-\frac {\cos (c+d x) \sqrt [3]{\sin (c+d x)}}{3 d (a+a \sin (c+d x))^2}\\ \end {align*}
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Mathematica [A]
time = 0.28, size = 121, normalized size = 0.66 \begin {gather*} \frac {\sec ^3(c+d x) \sqrt [3]{\sin (c+d x)} \left (80 \cos ^2(c+d x)^{3/2} \, _2F_1\left (\frac {1}{6},\frac {1}{2};\frac {7}{6};\sin ^2(c+d x)\right )+27 \cos ^2(c+d x)^{3/2} \, _2F_1\left (\frac {2}{3},\frac {5}{2};\frac {5}{3};\sin ^2(c+d x)\right ) \sin (c+d x)+4 (-25+5 \cos (2 (c+d x))+27 \sin (c+d x))\right )}{180 a^2 d} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 0.49, size = 0, normalized size = 0.00 \[\int \frac {\sin ^{\frac {1}{3}}\left (d x +c \right )}{\left (a +a \sin \left (d x +c \right )\right )^{2}}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \frac {\int \frac {\sqrt [3]{\sin {\left (c + d x \right )}}}{\sin ^{2}{\left (c + d x \right )} + 2 \sin {\left (c + d x \right )} + 1}\, dx}{a^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\sin \left (c+d\,x\right )}^{1/3}}{{\left (a+a\,\sin \left (c+d\,x\right )\right )}^2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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